Q1. Consider the series given below:4/12/95, I/I/96, 29/1/96, 26/2/96, ….The next term of the series is:
(a) 24/3/96 (b) 25/3/96 (c) 26/3/96 (d) 27/3/96
Answer: (a) 24/3/96
Explanation: Pattern of the series as follows:
Q2. The next pair of letters in the series AZ, CX, FU ……… is:
(a) JQ (b) KP (c) IR (d) JV
Answer: (a) JQ
Explanation: Pattern of the series as follows:
Q3. In the series POQ, SRT, VUW, …… , the blank space refers to:
(a) XYZ (b) XZY (c) YXZ (d) YZY
Answer: (a) XYZ
Explanation: Pattern of the series as follows:
Q4. Which one of the following satisfies the relationship Dda : aDD :: Rrb : ?
(a) DDA (b) RRR (c) bRR (d) BBr
Answer: (c) bRR
Explanation: The relationship between Dda and aDD seems to involve rearranging the letters and keeping their case the same. Applying the same logic to Rrb, we should get rRB. So, among the given options, (c) bRR fits the pattern.
Q5. What is the missing number ‘X’ of the series 7, X, 21, 31, 43?
(a) 11
(b) 12
(c) 13
(d) 14
Ans. (c)
Exp. The pattern of the series is as follows,
So, the missing number is 13.
Q6. Consider the following matrix
What is the missing number at’?’ in the matrix?
(a) 5 (b) 0
(c) 7 {d) 3
Ans. (a)
Exp. In each column, let the number at the top be x and the number at the bottom be y, then y = x (x-1)
As, in column I, 6=3(3-1)
Similarly, in column V. 20?(?-1)
20=5 (5-1)
20=5×4=20 = 20
?=5 6=6
Q7. Consider the following sequence that follows some arrangement: c_accaa_aa_bc_b. The letters that appear in the gaps are:
(a) abba (b) cbbb (c) bbbb (d) cccc
Answer: (b) cbbb
Explanation: ccacc/aabaa/bbcbb → cbbb. The option (b) cbbb is correct.
Q8. Which of the following 5s is not immediately preceded by a 3 but is immediately followed by 2019?
(a) 1
(b) 2
(c) 3
(d) none
Ans. (a) 7 3 5 7 4 3 1 5 7
Exp. Only one such 5 is possible, which is not immediately preceded by 3 but is immediately followed by 7.
Q9. What is ‘X’ in the sequence 132, 129, 124, 117, 106.93, X?
(a) 74
(b) 75
(c) 76
(d) 77
Ans. (c)
The pattern of the series is as follows:
Q10. What is ‘X’ in the sequence 4, 196, 16, 144, 36, 100, 64, X?
(a) 48
(b) 64
(c) 125
(d) 256
Ans. (b)
The pattern of the series is as follows:
Q11. If every alternative letter of the English alphabet from ‘B’ onwards (including ‘B’) is written in lowercase (small letters), and the remaining letters are capitalized, then how is the first month of the second half of the year written?
(a) JULY
(b) jULy
(c) july
(d) jUlY
Ans. (d)
Exp. According to the question, the English alphabet series is written as: AbCdEfGhIkMnOpQrStUvWxYz. The first month of the second half of the year is July, which will be written as ‘jUlY’.
Q12. What is the value of ‘X’ in the sequence 2, 7, 22, 67, 202, X, 1822?
(a) 603
(b) 605
(c) 607
(d) 608
Ans. (c)
The sequence of the series is as follows:
Q13. In the series _b_a_ba_b_abab_aab; fill in the six blanks using one of the following given four choices such that the series follows a specific order.
(a) bababa
(b) baabba
(c) bbaabb
(d) ababab
Ans. (d)
Exp. Sequences of the given series are as follows:
abb / aab / abb / aab / abb / aab / ababab
Q14. Images of consonants of the English alphabet (Capitals) are observed in a mirror. What is the number of images of these which do not look like their original shapes?
(a) 13
(b) 14
(c) 15
(d) 16
Ans. (b)
Exp. All the consonants of the English alphabet are:
B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, W, X, Y, Z
So, there are a total of 21 consonants. The number of consonants whose images look like them are:
H, M, T, V, W, X, and Y (Total 7)
The number of consonants whose images do not look like them = 21 – 7 = 14
Q15. You are given two identical sequences in two rows.
What is the entry in the place of C for the sequence-II?
(a) 2.5
(b) 5
(c) 9.375
(d) 32.8125
Ans. (c)
Exp. According to the sequence-1:
So, the entry in the place of C for the sequence-II is 9.375
Q16. Replace the incorrect term by the correct term in the given sequence: 3, 2, 7, 4, 13, 10, 21, 18, 31, 28, 43, 40 where odd terms and even terms follow the same pattern.
(a) 0
(b) 1
(c) 3
(d) 6
Ans. (a)
Exp. Given series:
Since odd terms and even terms follow the same pattern as per the given question, ‘2’ will be replaced with ‘0’.
Q17. In the English alphabet, the first 4 letters are written in opposite order and the next 4 letters are written in opposite order and so on and at the end Y and Z are interchanged. Which will be the fourth letter to the right of the 13th letter?
(a) N (b) T (c) H (d) I
Ans. (b)
Exp. The English alphabet is ABCD EFGH IJKL MNOP QRST UVWX YZ As per the question, letters are arranged as follows DCBA HGFE LKJI PONM TSRO XWVU ZY 4th letter to the right of the 13th letter13+4 = 17th letter The required letter is T
Q18. Consider the following sequence of numbers 51473985726315863852243496 How many odd numbers are followed by the odd number in the above sequence?
(a) 5 (b) 6 (c) 7 (d) 8
Ans. (b)
Exp. 514739857263 15 863852243496 Hence, there are 6 odd numbers, which are followed by an odd number The pairs are ’51’, ’73’, ’39’, ’57’, ’31’, ’15’.
Q19. Consider the following arrangement that has some missing letters abab_b_bcb_dcdcded_d (2020) The missing letters which complete the arrangement are
(a) a,b, c, d (b) a, b, d, e (c) a, c, c, e (d) b, c, d, e
Ans. (c)
Exp. Given series is as follows ab ab a/bcbcb/gdcdc/deded Missing letters = a, c, c, e
Q20. The letters from A to Z are numbered from 1 to 26 respectively. If GHI = 1578 and DEF = 912, then what is ABC equa to?
(a) 492 (b) 468 (c) 262 (d) 246
Ans. (d)
Exp. As. GHI 111 789 789×2=1578 and DEF 4 5 6 456×2=912 Similarly. A B C 1 2 3 123×2=246
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